11103210013 has 4 divisors (see below), whose sum is σ = 12689382880. Its totient is φ = 9517037148.

The previous prime is 11103209977. The next prime is 11103210023. The reversal of 11103210013 is 31001230111.

11103210013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31001230111 = 31 ⋅1000039681.

It is a cyclic number.

It is not a de Polignac number, because 11103210013 - 2²¹ = 11101112861 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11103209975 and 11103210002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11103210023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 793086423 + ... + 793086436.

It is an arithmetic number, because the mean of its divisors is an integer number (3172345720).

Almost surely, 2^11103210013 is an apocalyptic number.

It is an amenable number.

11103210013 is a deficient number, since it is larger than the sum of its proper divisors (1586172867).

11103210013 is an equidigital number, since it uses as much as digits as its factorization.

11103210013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1586172866.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11103210013 its reverse (31001230111), we get a palindrome (42104440124).

It can be divided in two parts, 1110 and 3210013, that added together give a palindrome (3211123).

The spelling of 11103210013 in words is "eleven billion, one hundred three million, two hundred ten thousand, thirteen".