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1110330130013 = 13731170000137
BaseRepresentation
bin10000001010000100110…
…101010011111001011101
310221010221211000202002122
4100022010311103321131
5121142424003130023
62210024552032325
7143135005245446
oct20120465237135
93833854022078
101110330130013
11398985459625
1215b2333926a5
138091bcb2740
143ba514042cd
151dd378202c8
hex10284d53e5d

1110330130013 has 8 divisors (see below), whose sum is σ = 1212120142968. Its totient is φ = 1010880117504.

The previous prime is 1110330129959. The next prime is 1110330130051. The reversal of 1110330130013 is 3100310330111.

It can be written as a sum of positive squares in 4 ways, for example, as 76729 + 1110330053284 = 277^2 + 1053722^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1110330130013 - 212 = 1110330125917 is a prime.

It is a super-4 number, since 4×11103301300134 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1110330129973 and 1110330130000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1110330130213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 584999120 + ... + 585001017.

It is an arithmetic number, because the mean of its divisors is an integer number (151515017871).

Almost surely, 21110330130013 is an apocalyptic number.

1110330130013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1110330130013 is a deficient number, since it is larger than the sum of its proper divisors (101790012955).

1110330130013 is a wasteful number, since it uses less digits than its factorization.

1110330130013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1170000223.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1110330130013 its reverse (3100310330111), we get a palindrome (4210640460124).

The spelling of 1110330130013 in words is "one trillion, one hundred ten billion, three hundred thirty million, one hundred thirty thousand, thirteen".

Divisors: 1 13 73 949 1170000137 15210001781 85410010001 1110330130013