111055000433 has 4 divisors (see below), whose sum is σ = 119597692788. Its totient is φ = 102512308080.

The previous prime is 111055000409. The next prime is 111055000453. The reversal of 111055000433 is 334000550111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334000550111 = 17 ⋅19647091183.

It can be written as a sum of positive squares in 2 ways, for example, as 8227034209 + 102827966224 = 90703^2 + 320668^2 .

It is not a de Polignac number, because 111055000433 - 2¹² = 111054996337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 111055000399 and 111055000408.

It is not an unprimeable number, because it can be changed into a prime (111055000453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4271346158 + ... + 4271346183.

It is an arithmetic number, because the mean of its divisors is an integer number (29899423197).

Almost surely, 2^111055000433 is an apocalyptic number.

111055000433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

111055000433 is a deficient number, since it is larger than the sum of its proper divisors (8542692355).

111055000433 is an equidigital number, since it uses as much as digits as its factorization.

111055000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8542692354.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 111055000433 its reverse (334000550111), we get a palindrome (445055550544).

The spelling of 111055000433 in words is "one hundred eleven billion, fifty-five million, four hundred thirty-three", and thus it is an aban number.