11110100111081 has 2 divisors, whose sum is σ = 11110100111082. Its totient is φ = 11110100111080.

The previous prime is 11110100111063. The next prime is 11110100111083. The reversal of 11110100111081 is 18011100101111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10722618760681 + 387481350400 = 3274541^2 + 622480^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110100111081 - 2³⁰ = 11109026369257 is a prime.

It is a super-3 number, since 3×11110100111081³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 11110100111083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11110100111083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555050055540 + 5555050055541.

It is an arithmetic number, because the mean of its divisors is an integer number (5555050055541).

Almost surely, 2^{11110100111081} is an apocalyptic number.

It is an amenable number.

11110100111081 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110100111081 is an equidigital number, since it uses as much as digits as its factorization.

11110100111081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 17.

Adding to 11110100111081 its reverse (18011100101111), we get a palindrome (29121200212192).

The spelling of 11110100111081 in words is "eleven trillion, one hundred ten billion, one hundred million, one hundred eleven thousand, eighty-one".