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11111001100141 is a prime number
BaseRepresentation
bin1010000110101111101101…
…0001100000111101101101
31110100012102202210210220111
42201223323101200331231
52424020312240201031
635344153510220021
72224512652026145
oct241537321407555
943305382723814
1011111001100141
1135a4170504408
1212b5477954611
136279bc154ab7
142a5abd6b1925
151440515ee1b1
hexa1afb460f6d

11111001100141 has 2 divisors, whose sum is σ = 11111001100142. Its totient is φ = 11111001100140.

The previous prime is 11111001100117. The next prime is 11111001100151. The reversal of 11111001100141 is 14100110011111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8347274397225 + 2763726702916 = 2889165^2 + 1662446^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111001100141 - 239 = 10561245286253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111001100151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500550070 + 5555500550071.

It is an arithmetic number, because the mean of its divisors is an integer number (5555500550071).

Almost surely, 211111001100141 is an apocalyptic number.

It is an amenable number.

11111001100141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111001100141 is an equidigital number, since it uses as much as digits as its factorization.

11111001100141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 11111001100141 its reverse (14100110011111), we get a palindrome (25211111111252).

The spelling of 11111001100141 in words is "eleven trillion, one hundred eleven billion, one million, one hundred thousand, one hundred forty-one".