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1111102441133 is a prime number
BaseRepresentation
bin10000001010110010110…
…111011100011010101101
310221012221122021012210012
4100022302313130122231
5121201014211104013
62210233341223005
7143163103630406
oct20126267343255
93835848235705
101111102441133
113992413a8383
1215b409b61a65
1380a12cbc579
143bac5c029ad
151dd805281a8
hex102b2ddc6ad

1111102441133 has 2 divisors, whose sum is σ = 1111102441134. Its totient is φ = 1111102441132.

The previous prime is 1111102441109. The next prime is 1111102441151. The reversal of 1111102441133 is 3311442011111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 684016664809 + 427085776324 = 827053^2 + 653518^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111102441133 - 26 = 1111102441069 is a prime.

It is a super-3 number, since 3×11111024411333 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111102441099 and 1111102441108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111102441433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555551220566 + 555551220567.

It is an arithmetic number, because the mean of its divisors is an integer number (555551220567).

Almost surely, 21111102441133 is an apocalyptic number.

It is an amenable number.

1111102441133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111102441133 is an equidigital number, since it uses as much as digits as its factorization.

1111102441133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 1111102441133 its reverse (3311442011111), we get a palindrome (4422544452244).

The spelling of 1111102441133 in words is "one trillion, one hundred eleven billion, one hundred two million, four hundred forty-one thousand, one hundred thirty-three".