11111200000141 has 2 divisors, whose sum is σ = 11111200000142. Its totient is φ = 11111200000140.

The previous prime is 11111200000099. The next prime is 11111200000151. The reversal of 11111200000141 is 14100000211111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8752994434116 + 2358205566025 = 2958546^2 + 1535645^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111200000141 - 2⁷ = 11111200000013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111200000151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555600000070 + 5555600000071.

It is an arithmetic number, because the mean of its divisors is an integer number (5555600000071).

Almost surely, 2^{11111200000141} is an apocalyptic number.

It is an amenable number.

11111200000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111200000141 is an equidigital number, since it uses as much as digits as its factorization.

11111200000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 11111200000141 its reverse (14100000211111), we get a palindrome (25211200211252).

The spelling of 11111200000141 in words is "eleven trillion, one hundred eleven billion, two hundred million, one hundred forty-one", and thus it is an aban number.