Base | Representation |
---|---|
bin | 10000001010110100100… |
… | …101001010001010011011 |
3 | 10221020000122101102120000 |
4 | 100022310211022022123 |
5 | 121201044041432303 |
6 | 2210240245504043 |
7 | 143163603246051 |
oct | 20126445121233 |
9 | 3836018342500 |
10 | 1111131202203 |
11 | 399256661a60 |
12 | 15b417712023 |
13 | 80a18c4c659 |
14 | 3bac996c1d1 |
15 | 1dd82d09da3 |
hex | 102b494a29b |
1111131202203 has 40 divisors (see below), whose sum is σ = 1810838405376. Its totient is φ = 673373401200.
The previous prime is 1111131202177. The next prime is 1111131202243. The reversal of 1111131202203 is 3022021311111.
It is not a de Polignac number, because 1111131202203 - 25 = 1111131202171 is a prime.
It is a super-2 number, since 2×11111312022032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1111131202243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 24204250 + ... + 24250112.
Almost surely, 21111131202203 is an apocalyptic number.
1111131202203 is a deficient number, since it is larger than the sum of its proper divisors (699707203173).
1111131202203 is a wasteful number, since it uses less digits than its factorization.
1111131202203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73077 (or 73068 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1111131202203 its reverse (3022021311111), we get a palindrome (4133152513314).
It can be divided in two parts, 111113 and 1202203, that added together give a square (1313316 = 11462).
The spelling of 1111131202203 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, two hundred two thousand, two hundred three".
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