| Base | Representation |
|---|---|
| bin | 110011101111011011… |
| … | …1001110000110000000 |
| 3 | 101121210200002101200201 |
| 4 | 1213132313032012000 |
| 5 | 3310024434400000 |
| 6 | 123013353254544 |
| 7 | 11012326421335 |
| oct | 1473667160600 |
| 9 | 347720071621 |
| 10 | 111113200000 |
| 11 | 43139560810 |
| 12 | 1964b704454 |
| 13 | a62a01cb2a |
| 14 | 5540d9a98c |
| 15 | 2d54bd996a |
| hex | 19dedce180 |
111113200000 has 192 divisors, whose sum is σ = 301844899440. Its totient is φ = 40403200000.
The previous prime is 111113199991. The next prime is 111113200019. The reversal of 111113200000 is 2311111.
It is a super-2 number, since 2×1111132000002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a self number, because there is not a number n which added to its sum of digits gives 111113200000.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4387374 + ... + 4412626.
Almost surely, 2111113200000 is an apocalyptic number.
111113200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111113200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (150922449720).
111113200000 is an abundant number, since it is smaller than the sum of its proper divisors (190731699440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111113200000 is an frugal number, since it uses more digits than its factorization.
111113200000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25303 (or 25271 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 111113200000 its reverse (2311111), we get a palindrome (111115511111).
Subtracting from 111113200000 its reverse (2311111), we obtain a square (111110888889 = 3333332).
It can be divided in two parts, 111113 and 200000, that added together give a palindrome (311113).
The spelling of 111113200000 in words is "one hundred eleven billion, one hundred thirteen million, two hundred thousand".
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