1111211123117 has 2 divisors, whose sum is σ = 1111211123118. Its totient is φ = 1111211123116.

The previous prime is 1111211123059. The next prime is 1111211123201. The reversal of 1111211123117 is 7113211121111.

It is a m-pointer prime, because the next prime (1111211123201) can be obtained adding 1111211123117 to its product of digits (84).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 844981954441 + 266229168676 = 919229^2 + 515974^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111211123117 - 2¹⁶ = 1111211057581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111211123092 and 1111211123101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111211129117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555605561558 + 555605561559.

It is an arithmetic number, because the mean of its divisors is an integer number (555605561559).

Almost surely, 2^{1111211123117} is an apocalyptic number.

It is an amenable number.

1111211123117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111211123117 is an equidigital number, since it uses as much as digits as its factorization.

1111211123117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 84, while the sum is 23.

Adding to 1111211123117 its reverse (7113211121111), we get a palindrome (8224422244228).

The spelling of 1111211123117 in words is "one trillion, one hundred eleven billion, two hundred eleven million, one hundred twenty-three thousand, one hundred seventeen".