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111124300013 is a prime number
BaseRepresentation
bin110011101111110000…
…1100100000011101101
3101121211102222100001022
41213133201210003231
53310040310100023
6123014431223525
711012522652026
oct1473741440355
9347742870038
10111124300013
1143144852381
1219653377ba5
13a62c40829c
145542649c4d
152d55b7d7c8
hex19df8640ed

111124300013 has 2 divisors, whose sum is σ = 111124300014. Its totient is φ = 111124300012.

The previous prime is 111124299991. The next prime is 111124300033. The reversal of 111124300013 is 310003421111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95151890089 + 15972409924 = 308467^2 + 126382^2 .

It is a cyclic number.

It is not a de Polignac number, because 111124300013 - 28 = 111124299757 is a prime.

It is a super-2 number, since 2×1111243000132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111124299964 and 111124300000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111124300033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55562150006 + 55562150007.

It is an arithmetic number, because the mean of its divisors is an integer number (55562150007).

Almost surely, 2111124300013 is an apocalyptic number.

It is an amenable number.

111124300013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111124300013 is an equidigital number, since it uses as much as digits as its factorization.

111124300013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 111124300013 its reverse (310003421111), we get a palindrome (421127721124).

The spelling of 111124300013 in words is "one hundred eleven billion, one hundred twenty-four million, three hundred thousand, thirteen".