Base | Representation |
---|---|
bin | 10000001010111110110… |
… | …000101111100011101101 |
3 | 10221020110112210102100002 |
4 | 100022332300233203231 |
5 | 121201421303323432 |
6 | 2210305230514045 |
7 | 143201046144164 |
oct | 20127660574355 |
9 | 3836415712302 |
10 | 1111302011117 |
11 | 399334017251 |
12 | 15b464965925 |
13 | 80a45455c0c |
14 | 3bb045123db |
15 | 1dd92ce9e62 |
hex | 102bec2f8ed |
1111302011117 has 2 divisors, whose sum is σ = 1111302011118. Its totient is φ = 1111302011116.
The previous prime is 1111302011077. The next prime is 1111302011119. The reversal of 1111302011117 is 7111102031111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1081404488836 + 29897522281 = 1039906^2 + 172909^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111302011117 - 212 = 1111302007021 is a prime.
Together with 1111302011119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111302011119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555651005558 + 555651005559.
It is an arithmetic number, because the mean of its divisors is an integer number (555651005559).
Almost surely, 21111302011117 is an apocalyptic number.
It is an amenable number.
1111302011117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111302011117 is an equidigital number, since it uses as much as digits as its factorization.
1111302011117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 20.
Adding to 1111302011117 its reverse (7111102031111), we get a palindrome (8222404042228).
The spelling of 1111302011117 in words is "one trillion, one hundred eleven billion, three hundred two million, eleven thousand, one hundred seventeen".
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