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111140003 = 1316751193
BaseRepresentation
bin1101001111111…
…01110010100011
321202010111102102
412213331302203
5211422440003
615010041015
72516450222
oct647756243
9252114372
10111140003
1157810147
123127916b
131a044220
1410a90cb9
159b55588
hex69fdca3

111140003 has 8 divisors (see below), whose sum is σ = 120408288. Its totient is φ = 101974464.

The previous prime is 111139969. The next prime is 111140027. The reversal of 111140003 is 300041111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 111140003 - 26 = 111139939 is a prime.

It is not an unprimeable number, because it can be changed into a prime (111140803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23426 + ... + 27767.

It is an arithmetic number, because the mean of its divisors is an integer number (15051036).

Almost surely, 2111140003 is an apocalyptic number.

111140003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

111140003 is a deficient number, since it is larger than the sum of its proper divisors (9268285).

111140003 is a wasteful number, since it uses less digits than its factorization.

111140003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51373.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 111140003 is about 10542.2959074388. The cubic root of 111140003 is about 480.7915224723.

Adding to 111140003 its reverse (300041111), we get a palindrome (411181114).

It can be divided in two parts, 1111 and 40003, that added together give a palindrome (41114).

The spelling of 111140003 in words is "one hundred eleven million, one hundred forty thousand, three".

Divisors: 1 13 167 2171 51193 665509 8549231 111140003