1111401211 has 2 divisors, whose sum is σ = 1111401212. Its totient is φ = 1111401210.

The previous prime is 1111401139. The next prime is 1111401229. The reversal of 1111401211 is 1121041111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1111401211 - 2⁹ = 1111400699 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111401191 and 1111401200.

It is not a weakly prime, because it can be changed into another prime (1111401241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555700605 + 555700606.

It is an arithmetic number, because the mean of its divisors is an integer number (555700606).

Almost surely, 2^1111401211 is an apocalyptic number.

1111401211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111401211 is an equidigital number, since it uses as much as digits as its factorization.

1111401211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

The square root of 1111401211 is about 33337.6845476707. The cubic root of 1111401211 is about 1035.8343015879.

Adding to 1111401211 its reverse (1121041111), we get a palindrome (2232442322).

The spelling of 1111401211 in words is "one billion, one hundred eleven million, four hundred one thousand, two hundred eleven".