Base | Representation |
---|---|
bin | 10100101100111001… |
… | …00110010101000111 |
3 | 1001200112222102002000 |
4 | 22112130212111013 |
5 | 140230141422043 |
6 | 5034455520343 |
7 | 542262363150 |
oct | 122634462507 |
9 | 31615872060 |
10 | 11114014023 |
11 | 4793631262 |
12 | 21a20890b3 |
13 | 1081736a78 |
14 | 7760ac927 |
15 | 450ab12d3 |
hex | 296726547 |
11114014023 has 64 divisors (see below), whose sum is σ = 19721594880. Its totient is φ = 6048117504.
The previous prime is 11114014019. The next prime is 11114014031. The reversal of 11114014023 is 32041041111.
11114014023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11114014023 - 22 = 11114014019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11114013987 and 11114014005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11114014063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1007365 + ... + 1018337.
It is an arithmetic number, because the mean of its divisors is an integer number (308149920).
Almost surely, 211114014023 is an apocalyptic number.
11114014023 is a deficient number, since it is larger than the sum of its proper divisors (8607580857).
11114014023 is a wasteful number, since it uses less digits than its factorization.
11114014023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11245 (or 11239 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 11114014023 its reverse (32041041111), we get a palindrome (43155055134).
The spelling of 11114014023 in words is "eleven billion, one hundred fourteen million, fourteen thousand, twenty-three".
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