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11114340341 = 133073897159
BaseRepresentation
bin10100101100111011…
…10101111111110101
31001200120120222200212
422112131311333311
5140230232342331
65034510515205
7542265222416
oct122635657765
931616528625
1011114340341
114793834445
1221a2205b05
13108181c460
1477615580d
15450b27d2b
hex296775ff5

11114340341 has 16 divisors (see below), whose sum is σ = 12040828800. Its totient is φ = 10198260288.

The previous prime is 11114340313. The next prime is 11114340343. The reversal of 11114340341 is 14304341111.

It is a cyclic number.

It is not a de Polignac number, because 11114340341 - 210 = 11114339317 is a prime.

It is a super-2 number, since 2×111143403412 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11114340343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1548920 + ... + 1556078.

It is an arithmetic number, because the mean of its divisors is an integer number (752551800).

Almost surely, 211114340341 is an apocalyptic number.

It is an amenable number.

11114340341 is a deficient number, since it is larger than the sum of its proper divisors (926488459).

11114340341 is a wasteful number, since it uses less digits than its factorization.

11114340341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7868.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11114340341 its reverse (14304341111), we get a palindrome (25418681452).

The spelling of 11114340341 in words is "eleven billion, one hundred fourteen million, three hundred forty thousand, three hundred forty-one".

Divisors: 1 13 307 389 3991 5057 7159 93067 119423 1552499 2197813 2784851 28571569 36203063 854949257 11114340341