11114433203130 has 160 divisors (see below), whose sum is σ = 29961280641600. Its totient is φ = 2956339772928.

The previous prime is 11114433203113. The next prime is 11114433203177. The reversal of 11114433203130 is 3130233441111.

11114433203130 is a `hidden beast` number, since 1 + 1 + 1 + 1 + 443 + 3 + 203 + 13 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11114433203094 and 11114433203103.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 604726281 + ... + 604744659.

It is an arithmetic number, because the mean of its divisors is an integer number (187258004010).

Almost surely, 2^{11114433203130} is an apocalyptic number.

11114433203130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11114433203130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14980640320800).

11114433203130 is an abundant number, since it is smaller than the sum of its proper divisors (18846847438470).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11114433203130 is a wasteful number, since it uses less digits than its factorization.

11114433203130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20250 (or 20241 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 11114433203130 its reverse (3130233441111), we get a palindrome (14244666644241).

The spelling of 11114433203130 in words is "eleven trillion, one hundred fourteen billion, four hundred thirty-three million, two hundred three thousand, one hundred thirty".