111200012130131 has 2 divisors, whose sum is σ = 111200012130132. Its totient is φ = 111200012130130.

The previous prime is 111200012130121. The next prime is 111200012130133. The reversal of 111200012130131 is 131031210002111.

It is a strong prime.

It is an emirp because it is prime and its reverse (131031210002111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111200012130131 - 2²² = 111200007935827 is a prime.

It is a super-4 number, since 4×111200012130131⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 111200012130133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111200012130133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600006065065 + 55600006065066.

It is an arithmetic number, because the mean of its divisors is an integer number (55600006065066).

Almost surely, 2^{111200012130131} is an apocalyptic number.

111200012130131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111200012130131 is an equidigital number, since it uses as much as digits as its factorization.

111200012130131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 111200012130131 its reverse (131031210002111), we get a palindrome (242231222132242).

The spelling of 111200012130131 in words is "one hundred eleven trillion, two hundred billion, twelve million, one hundred thirty thousand, one hundred thirty-one".