Base | Representation |
---|---|
bin | 10000001011101000011… |
… | …100011001110001110111 |
3 | 10221022021021200002122222 |
4 | 100023220130121301313 |
5 | 121204334314301403 |
6 | 2210502451312555 |
7 | 143224300165550 |
oct | 20135034316167 |
9 | 3838237602588 |
10 | 1112001322103 |
11 | 399662835a11 |
12 | 15b61abab75b |
13 | 80b272b37b9 |
14 | 3bb6d34b327 |
15 | 1ddd43d3338 |
hex | 102e8719c77 |
1112001322103 has 4 divisors (see below), whose sum is σ = 1270858653840. Its totient is φ = 953143990368.
The previous prime is 1112001322097. The next prime is 1112001322129. The reversal of 1112001322103 is 3012231002111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1112001322103 - 212 = 1112001318007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1112001321103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79428665858 + ... + 79428665871.
It is an arithmetic number, because the mean of its divisors is an integer number (317714663460).
Almost surely, 21112001322103 is an apocalyptic number.
1112001322103 is a deficient number, since it is larger than the sum of its proper divisors (158857331737).
1112001322103 is an equidigital number, since it uses as much as digits as its factorization.
1112001322103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158857331736.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1112001322103 its reverse (3012231002111), we get a palindrome (4124232324214).
The spelling of 1112001322103 in words is "one trillion, one hundred twelve billion, one million, three hundred twenty-two thousand, one hundred three".
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