Base | Representation |
---|---|
bin | 11001010010001100000110… |
… | …001001000110110000110111 |
3 | 112120201201110221120021210222 |
4 | 121102030012021012300313 |
5 | 104033404323413423111 |
6 | 1032301025233204555 |
7 | 32265004645306124 |
oct | 3122140611066067 |
9 | 476651427507728 |
10 | 111201101311031 |
11 | 32483138757596 |
12 | 1057b627a0075b |
13 | 4a082acaa87a4 |
14 | 1d6623a82974b |
15 | ccc8e0e427db |
hex | 652306246c37 |
111201101311031 has 2 divisors, whose sum is σ = 111201101311032. Its totient is φ = 111201101311030.
The previous prime is 111201101310931. The next prime is 111201101311049. The reversal of 111201101311031 is 130113101102111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111201101311031 - 210 = 111201101310007 is a prime.
It is a super-3 number, since 3×1112011013110313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111201101311051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600550655515 + 55600550655516.
It is an arithmetic number, because the mean of its divisors is an integer number (55600550655516).
Almost surely, 2111201101311031 is an apocalyptic number.
111201101311031 is a deficient number, since it is larger than the sum of its proper divisors (1).
111201101311031 is an equidigital number, since it uses as much as digits as its factorization.
111201101311031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 17.
Adding to 111201101311031 its reverse (130113101102111), we get a palindrome (241314202413142).
The spelling of 111201101311031 in words is "one hundred eleven trillion, two hundred one billion, one hundred one million, three hundred eleven thousand, thirty-one".
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