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111201120110112 = 2533085337543999
BaseRepresentation
bin11001010010001100000111…
…010000110100011000100000
3112120201201112020221101022020
4121102030013100310120200
5104033404343222010422
61032301031144141440
732265005264144004
oct3122140720643040
9476651466841266
10111201120110112
113248314832761a
121057b632167880
134a082b395b3c6
141d6623d120704
15ccc8e290795c
hex652307434620

111201120110112 has 48 divisors (see below), whose sum is σ = 291912409152000. Its totient is φ = 37065837641472.

The previous prime is 111201120110099. The next prime is 111201120110117. The reversal of 111201120110112 is 211011021102111.

It is a tau number, because it is divible by the number of its divisors (48).

It is a super-2 number, since 2×1112011201101122 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111201120110091 and 111201120110100.

It is not an unprimeable number, because it can be changed into a prime (111201120110117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15810112 + ... + 21733887.

It is an arithmetic number, because the mean of its divisors is an integer number (6081508524000).

Almost surely, 2111201120110112 is an apocalyptic number.

111201120110112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

111201120110112 is an abundant number, since it is smaller than the sum of its proper divisors (180711289041888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111201120110112 is a wasteful number, since it uses less digits than its factorization.

111201120110112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37574865 (or 37574857 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 15.

Adding to 111201120110112 its reverse (211011021102111), we get a palindrome (322212141212223).

The spelling of 111201120110112 in words is "one hundred eleven trillion, two hundred one billion, one hundred twenty million, one hundred ten thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 16 24 32 48 96 30853 61706 92559 123412 185118 246824 370236 493648 740472 987296 1480944 2961888 37543999 75087998 112631997 150175996 225263994 300351992 450527988 600703984 901055976 1201407968 1802111952 3604223904 1158345001147 2316690002294 3475035003441 4633380004588 6950070006882 9266760009176 13900140013764 18533520018352 27800280027528 37067040036704 55600560055056 111201120110112