Base | Representation |
---|---|
bin | 10000001011101001000… |
… | …010001010010011101111 |
3 | 10221022021222021222022102 |
4 | 100023221002022103233 |
5 | 121204344333021312 |
6 | 2210503443405315 |
7 | 143224450262156 |
oct | 20135102122357 |
9 | 3838258258272 |
10 | 1112011220207 |
11 | 399668386568 |
12 | 15b62238383b |
13 | 80b2936ab74 |
14 | 3bb707a659d |
15 | 1ddd51daec2 |
hex | 102e908a4ef |
1112011220207 has 2 divisors, whose sum is σ = 1112011220208. Its totient is φ = 1112011220206.
The previous prime is 1112011220191. The next prime is 1112011220209. The reversal of 1112011220207 is 7020221102111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112011220207 - 24 = 1112011220191 is a prime.
It is a super-2 number, since 2×11120112202072 (a number of 25 digits) contains 22 as substring.
Together with 1112011220209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112011220209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556005610103 + 556005610104.
It is an arithmetic number, because the mean of its divisors is an integer number (556005610104).
Almost surely, 21112011220207 is an apocalyptic number.
1112011220207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112011220207 is an equidigital number, since it uses as much as digits as its factorization.
1112011220207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 1112011220207 its reverse (7020221102111), we get a palindrome (8132232322318).
The spelling of 1112011220207 in words is "one trillion, one hundred twelve billion, eleven million, two hundred twenty thousand, two hundred seven".
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