Base | Representation |
---|---|
bin | 10000001011101001000… |
… | …101100001010110001001 |
3 | 10221022022000221201112102 |
4 | 100023221011201112021 |
5 | 121204400044213001 |
6 | 2210503514323145 |
7 | 143224460621114 |
oct | 20135105412611 |
9 | 3838260851472 |
10 | 1112012101001 |
11 | 39966892829a |
12 | 15b6227294b5 |
13 | 80b295b8a49 |
14 | 3bb7095557b |
15 | 1ddd5311e6b |
hex | 102e9161589 |
1112012101001 has 2 divisors, whose sum is σ = 1112012101002. Its totient is φ = 1112012101000.
The previous prime is 1112012100839. The next prime is 1112012101003. The reversal of 1112012101001 is 1001012102111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 661034041600 + 450978059401 = 813040^2 + 671549^2 .
It is a cyclic number.
It is not a de Polignac number, because 1112012101001 - 218 = 1112011838857 is a prime.
Together with 1112012101003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1112012101003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556006050500 + 556006050501.
It is an arithmetic number, because the mean of its divisors is an integer number (556006050501).
Almost surely, 21112012101001 is an apocalyptic number.
It is an amenable number.
1112012101001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112012101001 is an equidigital number, since it uses as much as digits as its factorization.
1112012101001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1112012101001 its reverse (1001012102111), we get a palindrome (2113024203112).
The spelling of 1112012101001 in words is "one trillion, one hundred twelve billion, twelve million, one hundred one thousand, one".
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