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11120200112111 is a prime number
BaseRepresentation
bin1010000111010001111110…
…0100111101011111101111
31110101002011212101001000112
42201310133210331133233
52424143132212041421
635352314401050235
72225256632241056
oct241643744753757
943332155331015
1011120200112111
1135a8061073242
1212b720462697b
13628826c0474c
142a63132cd39d
151443ddedc45b
hexa1d1f93d7ef

11120200112111 has 2 divisors, whose sum is σ = 11120200112112. Its totient is φ = 11120200112110.

The previous prime is 11120200112081. The next prime is 11120200112113. The reversal of 11120200112111 is 11121100202111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11120200112111 is a prime.

It is a super-3 number, since 3×111202001121113 (a number of 40 digits) contains 333 as substring.

Together with 11120200112113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11120200112113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560100056055 + 5560100056056.

It is an arithmetic number, because the mean of its divisors is an integer number (5560100056056).

Almost surely, 211120200112111 is an apocalyptic number.

11120200112111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120200112111 is an equidigital number, since it uses as much as digits as its factorization.

11120200112111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 11120200112111 its reverse (11121100202111), we get a palindrome (22241300314222).

The spelling of 11120200112111 in words is "eleven trillion, one hundred twenty billion, two hundred million, one hundred twelve thousand, one hundred eleven".