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11120200212012 = 22317371499887681
BaseRepresentation
bin1010000111010001111110…
…0101010101111000101100
31110101002011212120010001120
42201310133211111320230
52424143132223241022
635352314403140540
72225256633135243
oct241643745257054
943332155503046
1011120200212012
1135a8061131301
1212b7204674750
13628826c3b068
142a631331795a
151443de00bd5c
hexa1d1f955e2c

11120200212012 has 96 divisors (see below), whose sum is σ = 28405332849600. Its totient is φ = 3371619778560.

The previous prime is 11120200212007. The next prime is 11120200212013. The reversal of 11120200212012 is 21021200202111.

It is a super-3 number, since 3×111202002120123 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11120200211982 and 11120200212000.

It is not an unprimeable number, because it can be changed into a prime (11120200212013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3819189 + ... + 6068492.

It is an arithmetic number, because the mean of its divisors is an integer number (295888883850).

Almost surely, 211120200212012 is an apocalyptic number.

11120200212012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11120200212012 is an abundant number, since it is smaller than the sum of its proper divisors (17285132637588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11120200212012 is a wasteful number, since it uses less digits than its factorization.

11120200212012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9887891 (or 9887889 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 11120200212012 its reverse (21021200202111), we get a palindrome (32141400414123).

Subtracting 11120200212012 from its reverse (21021200202111), we obtain a palindrome (9900999990099).

The spelling of 11120200212012 in words is "eleven trillion, one hundred twenty billion, two hundred million, two hundred twelve thousand, twelve".

Divisors: 1 2 3 4 6 12 17 34 37 51 68 74 102 111 148 149 204 222 298 444 447 596 629 894 1258 1788 1887 2516 2533 3774 5066 5513 7548 7599 10132 11026 15198 16539 22052 30396 33078 66156 93721 187442 281163 374884 562326 1124652 9887681 19775362 29663043 39550724 59326086 118652172 168090577 336181154 365844197 504271731 672362308 731688394 1008543462 1097532591 1463376788 1473264469 2017086924 2195065182 2946528938 4390130364 4419793407 5893057876 6219351349 8839586814 12438702698 17679173628 18658054047 24877405396 25045495973 37316108094 50090991946 54510785353 74632216188 75136487919 100181983892 109021570706 150272975838 163532356059 218043141412 300545951676 327064712118 654129424236 926683351001 1853366702002 2780050053003 3706733404004 5560100106006 11120200212012