111204261317 has 2 divisors, whose sum is σ = 111204261318. Its totient is φ = 111204261316.

The previous prime is 111204261241. The next prime is 111204261319. The reversal of 111204261317 is 713162402111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110671990276 + 532271041 = 332674^2 + 23071^2 .

It is a cyclic number.

It is not a de Polignac number, because 111204261317 - 2¹⁸ = 111203999173 is a prime.

It is a super-4 number, since 4×111204261317⁴ (a number of 45 digits) contains 4444 as substring.

Together with 111204261319, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111204261317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111204261319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55602130658 + 55602130659.

It is an arithmetic number, because the mean of its divisors is an integer number (55602130659).

Almost surely, 2^111204261317 is an apocalyptic number.

It is an amenable number.

111204261317 is a deficient number, since it is larger than the sum of its proper divisors (1).

111204261317 is an equidigital number, since it uses as much as digits as its factorization.

111204261317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 111204261317 its reverse (713162402111), we get a palindrome (824366663428).

The spelling of 111204261317 in words is "one hundred eleven billion, two hundred four million, two hundred sixty-one thousand, three hundred seventeen".