Search a number
-
+
111211011101120 = 2657239464944683
BaseRepresentation
bin11001010010010101010100…
…110011111101000111000000
3112120202200001120120210012112
4121102111110303331013000
5104034040122320213440
61032305344434314452
732265505346162330
oct3122252463750700
9476680046523175
10111211011101120
1132487363557557
1210581532728a28
134a091cbb9c5c8
141d668da9c90c0
15ccccc0e31965
hex652554cfd1c0

111211011101120 has 224 divisors, whose sum is σ = 303991329024000. Its totient is φ = 37960934989824.

The previous prime is 111211011101027. The next prime is 111211011101143. The reversal of 111211011101120 is 21101110112111.

111211011101120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (224).

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 111211011101095 and 111211011101104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2488866299 + ... + 2488910981.

Almost surely, 2111211011101120 is an apocalyptic number.

111211011101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111211011101120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (151995664512000).

111211011101120 is an abundant number, since it is smaller than the sum of its proper divisors (192780317922880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111211011101120 is a wasteful number, since it uses less digits than its factorization.

111211011101120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49595 (or 49585 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 14.

Adding to 111211011101120 its reverse (21101110112111), we get a palindrome (132312121213231).

It can be divided in two parts, 11121101 and 1101120, that added together give a palindrome (12222221).

The spelling of 111211011101120 in words is "one hundred eleven trillion, two hundred eleven billion, eleven million, one hundred one thousand, one hundred twenty".