Base | Representation |
---|---|
bin | 10100101101110000… |
… | …00000111111001111 |
3 | 1001201001111112220011 |
4 | 22112320000333033 |
5 | 140234011413403 |
6 | 5035313534051 |
7 | 542410435555 |
oct | 122670007717 |
9 | 31631445804 |
10 | 11121201103 |
11 | 479769aaa1 |
12 | 21a4574327 |
13 | 108308218c |
14 | 77701dbd5 |
15 | 451530a6d |
hex | 296e00fcf |
11121201103 has 4 divisors (see below), whose sum is σ = 11128097448. Its totient is φ = 11114304760.
The previous prime is 11121201071. The next prime is 11121201127. The reversal of 11121201103 is 30110212111.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11121201103 - 25 = 11121201071 is a prime.
It is a super-2 number, since 2×111212011032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11121201193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3445753 + ... + 3448978.
It is an arithmetic number, because the mean of its divisors is an integer number (2782024362).
Almost surely, 211121201103 is an apocalyptic number.
11121201103 is a deficient number, since it is larger than the sum of its proper divisors (6896345).
11121201103 is an equidigital number, since it uses as much as digits as its factorization.
11121201103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6896344.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11121201103 its reverse (30110212111), we get a palindrome (41231413214).
The spelling of 11121201103 in words is "eleven billion, one hundred twenty-one million, two hundred one thousand, one hundred three".
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