Base | Representation |
---|---|
bin | 1010000111010101101111… |
… | …0101001100110010100111 |
3 | 1110101011210022112120021122 |
4 | 2201311123311030302213 |
5 | 2424202220004031043 |
6 | 35353002552004155 |
7 | 2225323655536013 |
oct | 241653365146247 |
9 | 43334708476248 |
10 | 11121211002023 |
11 | 35a852a754851 |
12 | 12b744709065b |
13 | 628958485565 |
14 | 2a63ab673543 |
15 | 14444cb20368 |
hex | a1d5bd4cca7 |
11121211002023 has 2 divisors, whose sum is σ = 11121211002024. Its totient is φ = 11121211002022.
The previous prime is 11121211001987. The next prime is 11121211002053. The reversal of 11121211002023 is 32020011212111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121211002023 - 216 = 11121210936487 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11121211001992 and 11121211002010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121211002053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560605501011 + 5560605501012.
It is an arithmetic number, because the mean of its divisors is an integer number (5560605501012).
Almost surely, 211121211002023 is an apocalyptic number.
11121211002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121211002023 is an equidigital number, since it uses as much as digits as its factorization.
11121211002023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11121211002023 its reverse (32020011212111), we get a palindrome (43141222214134).
The spelling of 11121211002023 in words is "eleven trillion, one hundred twenty-one billion, two hundred eleven million, two thousand, twenty-three".
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