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111213320153055 = 3523322357449719
BaseRepresentation
bin11001010010010111011110…
…011100010010011111011111
3112120202220000111110202222120
4121102113132130102133133
5104034104334424344210
61032310405521314023
732265616514614221
oct3122273634223737
9476686014422876
10111213320153055
11324883389a043a
1210581a77a95913
134a094a9393923
141d66a79532411
15cccda89e0270
hex6525de7127df

111213320153055 has 16 divisors (see below), whose sum is σ = 185677891038720. Its totient is φ = 56734911150368.

The previous prime is 111213320153029. The next prime is 111213320153093. The reversal of 111213320153055 is 550351023312111.

It is a cyclic number.

It is not a de Polignac number, because 111213320153055 - 223 = 111213311764447 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 161178724515 + ... + 161178725204.

It is an arithmetic number, because the mean of its divisors is an integer number (11604868189920).

Almost surely, 2111213320153055 is an apocalyptic number.

111213320153055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

111213320153055 is a deficient number, since it is larger than the sum of its proper divisors (74464570885665).

111213320153055 is a wasteful number, since it uses less digits than its factorization.

111213320153055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 322357449750.

The product of its (nonzero) digits is 13500, while the sum is 33.

Adding to 111213320153055 its reverse (550351023312111), we get a palindrome (661564343465166).

The spelling of 111213320153055 in words is "one hundred eleven trillion, two hundred thirteen billion, three hundred twenty million, one hundred fifty-three thousand, fifty-five".

Divisors: 1 3 5 15 23 69 115 345 322357449719 967072349157 1611787248595 4835361745785 7414221343537 22242664030611 37071106717685 111213320153055