Base | Representation |
---|---|
bin | 11001010010010111011110… |
… | …011100010010100000001100 |
3 | 112120202220000111110210001020 |
4 | 121102113132130102200030 |
5 | 104034104334424344400 |
6 | 1032310405521314140 |
7 | 32265616514614314 |
oct | 3122273634224014 |
9 | 476686014423036 |
10 | 111213320153100 |
11 | 324883389a0480 |
12 | 10581a77a95950 |
13 | 4a094a9393959 |
14 | 1d66a79532444 |
15 | cccda89e02a0 |
hex | 6525de71280c |
111213320153100 has 144 divisors (see below), whose sum is σ = 351517906414080. Its totient is φ = 26923306668800.
The previous prime is 111213320153093. The next prime is 111213320153171. The reversal of 111213320153100 is 1351023312111.
It is a super-2 number, since 2×1112133201531002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 21063327 + ... + 25808726.
It is an arithmetic number, because the mean of its divisors is an integer number (2441096572320).
Almost surely, 2111213320153100 is an apocalyptic number.
111213320153100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
111213320153100 is an abundant number, since it is smaller than the sum of its proper divisors (240304586260980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111213320153100 is a wasteful number, since it uses less digits than its factorization.
111213320153100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46872800 (or 46872793 counting only the distinct ones).
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 111213320153100 its reverse (1351023312111), we get a palindrome (112564343465211).
The spelling of 111213320153100 in words is "one hundred eleven trillion, two hundred thirteen billion, three hundred twenty million, one hundred fifty-three thousand, one hundred".
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