Base | Representation |
---|---|
bin | 10100101101110001… |
… | …00110011011000011 |
3 | 1001201001210100020010 |
4 | 22112320212123003 |
5 | 140234031320220 |
6 | 5035321120003 |
7 | 542411644602 |
oct | 122670463303 |
9 | 31631710203 |
10 | 11121354435 |
11 | 4797795214 |
12 | 21a4629003 |
13 | 1083106bc9 |
14 | 77705da39 |
15 | 4515611e0 |
hex | 296e266c3 |
11121354435 has 16 divisors (see below), whose sum is σ = 17865066240. Its totient is φ = 5907756000.
The previous prime is 11121354347. The next prime is 11121354463. The reversal of 11121354435 is 53445312111.
11121354435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11121354435 - 211 = 11121352387 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1473175 + ... + 1480704.
It is an arithmetic number, because the mean of its divisors is an integer number (1116566640).
Almost surely, 211121354435 is an apocalyptic number.
11121354435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11121354435 is a deficient number, since it is larger than the sum of its proper divisors (6743711805).
11121354435 is a wasteful number, since it uses less digits than its factorization.
11121354435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2954138.
The product of its digits is 7200, while the sum is 30.
Adding to 11121354435 its reverse (53445312111), we get a palindrome (64566666546).
The spelling of 11121354435 in words is "eleven billion, one hundred twenty-one million, three hundred fifty-four thousand, four hundred thirty-five".
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