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11122102133 = 13184901543
BaseRepresentation
bin10100101101110110…
…11100111101110101
31001201010012022212122
422112323130331311
5140234224232013
65035345125325
7542421210512
oct122673347565
931633168778
1011122102133
114798155a4a
1221a4929845
13108330932c
147771b6309
1545165ca08
hex296edcf75

11122102133 has 4 divisors (see below), whose sum is σ = 11207003808. Its totient is φ = 11037200460.

The previous prime is 11122102109. The next prime is 11122102141. The reversal of 11122102133 is 33120122111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33120122111 = 75144101361.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11122102133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11122102163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42450641 + ... + 42450902.

It is an arithmetic number, because the mean of its divisors is an integer number (2801750952).

Almost surely, 211122102133 is an apocalyptic number.

It is an amenable number.

11122102133 is a deficient number, since it is larger than the sum of its proper divisors (84901675).

11122102133 is an equidigital number, since it uses as much as digits as its factorization.

11122102133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84901674.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11122102133 its reverse (33120122111), we get a palindrome (44242224244).

The spelling of 11122102133 in words is "eleven billion, one hundred twenty-two million, one hundred two thousand, one hundred thirty-three".

Divisors: 1 131 84901543 11122102133