Base | Representation |
---|---|
bin | 11001010010100000111001… |
… | …001110001101011001001100 |
3 | 112120210212010021210220021221 |
4 | 121102200321032031121030 |
5 | 104034241042334422104 |
6 | 1032315201221333124 |
7 | 32266425233501620 |
oct | 3122407116153114 |
9 | 476725107726257 |
10 | 111223433123404 |
11 | 32491658455778 |
12 | 10583a1a8671a4 |
13 | 4a0a42b5b6454 |
14 | 1d673586a1180 |
15 | ccd29b765c54 |
hex | 65283938d64c |
111223433123404 has 96 divisors (see below), whose sum is σ = 245878993704960. Its totient is φ = 42894063455232.
The previous prime is 111223433123399. The next prime is 111223433123501. The reversal of 111223433123404 is 404321334322111.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (34).
It is a self number, because there is not a number n which added to its sum of digits gives 111223433123404.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23079009 + ... + 27478855.
It is an arithmetic number, because the mean of its divisors is an integer number (2561239517760).
Almost surely, 2111223433123404 is an apocalyptic number.
111223433123404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111223433123404, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (122939496852480).
111223433123404 is an abundant number, since it is smaller than the sum of its proper divisors (134655560581556).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111223433123404 is a wasteful number, since it uses less digits than its factorization.
111223433123404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4402207 (or 4402205 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 111223433123404 its reverse (404321334322111), we get a palindrome (515544767445515).
The spelling of 111223433123404 in words is "one hundred eleven trillion, two hundred twenty-three billion, four hundred thirty-three million, one hundred twenty-three thousand, four hundred four".
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