Base | Representation |
---|---|
bin | 1010000111011100011010… |
… | …0010010100010010111111 |
3 | 1110101100102002010202122020 |
4 | 2201313012202110102333 |
5 | 2424214401302323033 |
6 | 35353500342251223 |
7 | 2225416224226230 |
oct | 241670642242277 |
9 | 43340362122566 |
10 | 11123001214143 |
11 | 35a92692336a5 |
12 | 12b7866726b13 |
13 | 628b82329480 |
14 | 2a64db31d087 |
15 | 144504d936b3 |
hex | a1dc68944bf |
11123001214143 has 64 divisors (see below), whose sum is σ = 19276224307200. Its totient is φ = 5544372670848.
The previous prime is 11123001214103. The next prime is 11123001214159. The reversal of 11123001214143 is 34141210032111.
11123001214143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11123001214143 - 213 = 11123001205951 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11123001214103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10150293 + ... + 11192606.
It is an arithmetic number, because the mean of its divisors is an integer number (301191004800).
Almost surely, 211123001214143 is an apocalyptic number.
11123001214143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11123001214143 is a deficient number, since it is larger than the sum of its proper divisors (8153223093057).
11123001214143 is a wasteful number, since it uses less digits than its factorization.
11123001214143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21343028.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 11123001214143 its reverse (34141210032111), we get a palindrome (45264211246254).
The spelling of 11123001214143 in words is "eleven trillion, one hundred twenty-three billion, one million, two hundred fourteen thousand, one hundred forty-three".
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