Base | Representation |
---|---|
bin | 1010000111011101100100… |
… | …1001010111100100010111 |
3 | 1110101101012211122112102122 |
4 | 2201313121021113210113 |
5 | 2424221021220103142 |
6 | 35353551334330155 |
7 | 2225430035141603 |
oct | 241673111274427 |
9 | 43341184575378 |
10 | 11123313441047 |
11 | 35a94094a9365 |
12 | 12b79331b995b |
13 | 628c01c18612 |
14 | 2a652a996503 |
15 | 1445224ba1d2 |
hex | a1dd9257917 |
11123313441047 has 2 divisors, whose sum is σ = 11123313441048. Its totient is φ = 11123313441046.
The previous prime is 11123313440969. The next prime is 11123313441143. The reversal of 11123313441047 is 74014431332111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11123313441047 - 212 = 11123313436951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11123313440998 and 11123313441016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11123313441347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561656720523 + 5561656720524.
It is an arithmetic number, because the mean of its divisors is an integer number (5561656720524).
Almost surely, 211123313441047 is an apocalyptic number.
11123313441047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11123313441047 is an equidigital number, since it uses as much as digits as its factorization.
11123313441047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 11123313441047 its reverse (74014431332111), we get a palindrome (85137744773158).
The spelling of 11123313441047 in words is "eleven trillion, one hundred twenty-three billion, three hundred thirteen million, four hundred forty-one thousand, forty-seven".
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