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1112400035 = 5222480007
BaseRepresentation
bin100001001001101…
…1110000010100011
32212112011202222022
41002103132002203
54234233300120
6302214332055
736365146535
oct10223360243
92775152868
101112400035
11520a1467a
1227065a02b
13149602a96
14a7a49855
15679d5025
hex424de0a3

1112400035 has 4 divisors (see below), whose sum is σ = 1334880048. Its totient is φ = 889920024.

The previous prime is 1112400019. The next prime is 1112400059. The reversal of 1112400035 is 5300042111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1112400035 - 24 = 1112400019 is a prime.

It is a super-3 number, since 3×11124000353 (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112399986 and 1112400022.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111239999 + ... + 111240008.

It is an arithmetic number, because the mean of its divisors is an integer number (333720012).

Almost surely, 21112400035 is an apocalyptic number.

1112400035 is a deficient number, since it is larger than the sum of its proper divisors (222480013).

1112400035 is an equidigital number, since it uses as much as digits as its factorization.

1112400035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222480012.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1112400035 is about 33352.6615879453. The cubic root of 1112400035 is about 1036.1445125079.

Adding to 1112400035 its reverse (5300042111), we get a palindrome (6412442146).

The spelling of 1112400035 in words is "one billion, one hundred twelve million, four hundred thousand, thirty-five".

Divisors: 1 5 222480007 1112400035