111243313103 has 4 divisors (see below), whose sum is σ = 119800491048. Its totient is φ = 102686135160.

The previous prime is 111243313057. The next prime is 111243313109. The reversal of 111243313103 is 301313342111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 111243313103 - 2¹⁰ = 111243312079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111243313109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4278588953 + ... + 4278588978.

It is an arithmetic number, because the mean of its divisors is an integer number (29950122762).

Almost surely, 2^111243313103 is an apocalyptic number.

111243313103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

111243313103 is a deficient number, since it is larger than the sum of its proper divisors (8557177945).

111243313103 is an equidigital number, since it uses as much as digits as its factorization.

111243313103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8557177944.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 111243313103 its reverse (301313342111), we get a palindrome (412556655214).

The spelling of 111243313103 in words is "one hundred eleven billion, two hundred forty-three million, three hundred thirteen thousand, one hundred three".