11130000020131 has 4 divisors (see below), whose sum is σ = 11132695592200. Its totient is φ = 11127304448064.

The previous prime is 11130000020081. The next prime is 11130000020177. The reversal of 11130000020131 is 13102000003111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11130000020131 - 2¹⁵ = 11129999987363 is a prime.

It is a super-2 number, since 2×11130000020131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11130000000131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1347779841 + ... + 1347788098.

It is an arithmetic number, because the mean of its divisors is an integer number (2783173898050).

Almost surely, 2^{11130000020131} is an apocalyptic number.

11130000020131 is a deficient number, since it is larger than the sum of its proper divisors (2695572069).

11130000020131 is an equidigital number, since it uses as much as digits as its factorization.

11130000020131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2695572068.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11130000020131 its reverse (13102000003111), we get a palindrome (24232000023242).

The spelling of 11130000020131 in words is "eleven trillion, one hundred thirty billion, twenty thousand, one hundred thirty-one".