1113001132303 has 2 divisors, whose sum is σ = 1113001132304. Its totient is φ = 1113001132302.

The previous prime is 1113001132301. The next prime is 1113001132319. The reversal of 1113001132303 is 3032311003111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1113001132303 - 2¹ = 1113001132301 is a prime.

It is a super-2 number, since 2×1113001132303² (a number of 25 digits) contains 22 as substring.

Together with 1113001132301, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113001132301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556500566151 + 556500566152.

It is an arithmetic number, because the mean of its divisors is an integer number (556500566152).

Almost surely, 2^{1113001132303} is an apocalyptic number.

1113001132303 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113001132303 is an equidigital number, since it uses as much as digits as its factorization.

1113001132303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1113001132303 its reverse (3032311003111), we get a palindrome (4145312135414).

The spelling of 1113001132303 in words is "one trillion, one hundred thirteen billion, one million, one hundred thirty-two thousand, three hundred three".