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11130011575 = 52835363861
BaseRepresentation
bin10100101110110011…
…00111111110110111
31001201200002011120221
422113121213332313
5140243240332300
65040230435211
7542545352224
oct122731477667
931650064527
1011130011575
1147a1668481
1221a7502b07
131084b48487
1477827494b
154521c131a
hex297667fb7

11130011575 has 12 divisors (see below), whose sum is σ = 13967496648. Its totient is φ = 8796730400.

The previous prime is 11130011573. The next prime is 11130011591. The reversal of 11130011575 is 57511003111.

It is not a de Polignac number, because 11130011575 - 21 = 11130011573 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11130011573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2679856 + ... + 2684005.

It is an arithmetic number, because the mean of its divisors is an integer number (1163958054).

Almost surely, 211130011575 is an apocalyptic number.

11130011575 is a deficient number, since it is larger than the sum of its proper divisors (2837485073).

11130011575 is an equidigital number, since it uses as much as digits as its factorization.

11130011575 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5363954 (or 5363949 counting only the distinct ones).

The product of its (nonzero) digits is 525, while the sum is 25.

Adding to 11130011575 its reverse (57511003111), we get a palindrome (68641014686).

The spelling of 11130011575 in words is "eleven billion, one hundred thirty million, eleven thousand, five hundred seventy-five".

Divisors: 1 5 25 83 415 2075 5363861 26819305 134096525 445200463 2226002315 11130011575