Base | Representation |
---|---|
bin | 10100101110110100… |
… | …00010111110000000 |
3 | 1001201200021210012220 |
4 | 22113122002332000 |
5 | 140243302401422 |
6 | 5040233051040 |
7 | 542546322414 |
oct | 122732027600 |
9 | 31650253186 |
10 | 11130122112 |
11 | 47a173352a |
12 | 21a7556a80 |
13 | 1084b86895 |
14 | 7782a2d44 |
15 | 4521e3e5c |
hex | 297682f80 |
11130122112 has 64 divisors (see below), whose sum is σ = 30122260560. Its totient is φ = 3640033280.
The previous prime is 11130122111. The next prime is 11130122147. The reversal of 11130122112 is 21122103111.
It is a tau number, because it is divible by the number of its divisors (64).
It is a junction number, because it is equal to n+sod(n) for n = 11130122091 and 11130122100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11130122111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 253089 + ... + 293792.
Almost surely, 211130122112 is an apocalyptic number.
11130122112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11130122112 is an abundant number, since it is smaller than the sum of its proper divisors (18992138448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11130122112 is an equidigital number, since it uses as much as digits as its factorization.
11130122112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 546951 (or 546939 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11130122112 its reverse (21122103111), we get a palindrome (32252225223).
The spelling of 11130122112 in words is "eleven billion, one hundred thirty million, one hundred twenty-two thousand, one hundred twelve".
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