1113013300031 has 2 divisors, whose sum is σ = 1113013300032. Its totient is φ = 1113013300030.

The previous prime is 1113013299997. The next prime is 1113013300033. The reversal of 1113013300031 is 1300033103111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1113013300031 - 2¹⁴ = 1113013283647 is a prime.

It is a super-2 number, since 2×1113013300031² (a number of 25 digits) contains 22 as substring.

Together with 1113013300033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1113013299982 and 1113013300009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113013300033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556506650015 + 556506650016.

It is an arithmetic number, because the mean of its divisors is an integer number (556506650016).

Almost surely, 2^{1113013300031} is an apocalyptic number.

1113013300031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113013300031 is an equidigital number, since it uses as much as digits as its factorization.

1113013300031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1113013300031 its reverse (1300033103111), we get a palindrome (2413046403142).

The spelling of 1113013300031 in words is "one trillion, one hundred thirteen billion, thirteen million, three hundred thousand, thirty-one".