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111302013020 = 22511505918241
BaseRepresentation
bin110011110101000011…
…1011111000001011100
3101122021211101002110112
41213222013133001130
53310421303404040
6123044220225152
711020111333532
oct1475207370134
9348254332415
10111302013020
11432260a2830
12196a299b1b8
13a65a18b203
14555c0aa152
152d66584365
hex19ea1df05c

111302013020 has 24 divisors (see below), whose sum is σ = 254982793968. Its totient is φ = 40473459200.

The previous prime is 111302012999. The next prime is 111302013037. The reversal of 111302013020 is 20310203111.

It is a junction number, because it is equal to n+sod(n) for n = 111302012986 and 111302013004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 252958901 + ... + 252959340.

It is an arithmetic number, because the mean of its divisors is an integer number (10624283082).

Almost surely, 2111302013020 is an apocalyptic number.

111302013020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

111302013020 is an abundant number, since it is smaller than the sum of its proper divisors (143680780948).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111302013020 is a wasteful number, since it uses less digits than its factorization.

111302013020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505918261 (or 505918259 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 111302013020 its reverse (20310203111), we get a palindrome (131612216131).

The spelling of 111302013020 in words is "one hundred eleven billion, three hundred two million, thirteen thousand, twenty".

Divisors: 1 2 4 5 10 11 20 22 44 55 110 220 505918241 1011836482 2023672964 2529591205 5059182410 5565100651 10118364820 11130201302 22260402604 27825503255 55651006510 111302013020