Search a number
-
+
1113095925643 = 1385622763511
BaseRepresentation
bin10000001100101001101…
…011111110111110001011
310221102002120100201102211
4100030221223332332023
5121214110024110033
62211203232405551
7143263361154532
oct20145153767613
93842076321384
101113095925643
1139a0746a4839
1215b8856a68b7
1380c6ccc50c0
143bc34883319
151de4a5502cd
hex10329afef8b

1113095925643 has 4 divisors (see below), whose sum is σ = 1198718689168. Its totient is φ = 1027473162120.

The previous prime is 1113095925587. The next prime is 1113095925647. The reversal of 1113095925643 is 3465295903111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113095925643 - 221 = 1113093828491 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1113095925647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42811381743 + ... + 42811381768.

It is an arithmetic number, because the mean of its divisors is an integer number (299679672292).

Almost surely, 21113095925643 is an apocalyptic number.

1113095925643 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1113095925643 is a deficient number, since it is larger than the sum of its proper divisors (85622763525).

1113095925643 is an equidigital number, since it uses as much as digits as its factorization.

1113095925643 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85622763524.

The product of its (nonzero) digits is 874800, while the sum is 49.

The spelling of 1113095925643 in words is "one trillion, one hundred thirteen billion, ninety-five million, nine hundred twenty-five thousand, six hundred forty-three".

Divisors: 1 13 85622763511 1113095925643