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11131103301120 = 2932511372235323
BaseRepresentation
bin1010000111111010100101…
…1101010100111000000000
31110102010022201122102112200
42201332221131110320000
52424332444421113440
635401320330153200
72226124054643115
oct241765135247000
943363281572480
1011131103301120
113601746698550
1212b9347b82800
13629873a63c8a
142a6a6939c90c
1514482b306c30
hexa1fa9754e00

11131103301120 has 960 divisors, whose sum is σ = 43393146660864. Its totient is φ = 2613253570560.

The previous prime is 11131103301103. The next prime is 11131103301161. The reversal of 11131103301120 is 2110330113111.

11131103301120 is a `hidden beast` number, since 1 + 1 + 1 + 311 + 0 + 330 + 1 + 1 + 20 = 666.

It is a tau number, because it is divible by the number of its divisors (960).

It is a super-2 number, since 2×111311033011202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 11131103301093 and 11131103301102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2091130779 + ... + 2091136101.

Almost surely, 211131103301120 is an apocalyptic number.

11131103301120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11131103301120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21696573330432).

11131103301120 is an abundant number, since it is smaller than the sum of its proper divisors (32262043359744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11131103301120 is a wasteful number, since it uses less digits than its factorization.

11131103301120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5623 (or 5604 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 11131103301120 its reverse (2110330113111), we get a palindrome (13241433414231).

It can be divided in two parts, 11 and 131103301120, that added together give a palindrome (131103301131).

The spelling of 11131103301120 in words is "eleven trillion, one hundred thirty-one billion, one hundred three million, three hundred one thousand, one hundred twenty".