Base | Representation |
---|---|
bin | 100001001011000… |
… | …1100001000011000 |
3 | 2212120112000010120 |
4 | 1002112030020120 |
5 | 4234424104422 |
6 | 302241513240 |
7 | 36404206506 |
oct | 10226141030 |
9 | 2776460116 |
10 | 1113113112 |
11 | 5213613a1 |
12 | 270942820 |
13 | 1497c2517 |
14 | a7b93676 |
15 | 67ac645c |
hex | 4258c218 |
1113113112 has 32 divisors (see below), whose sum is σ = 2802811200. Its totient is φ = 368367264.
The previous prime is 1113113107. The next prime is 1113113117. The reversal of 1113113112 is 2113113111.
It is an interprime number because it is at equal distance from previous prime (1113113107) and next prime (1113113117).
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 1113113091 and 1113113100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113113117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163498 + ... + 170169.
It is an arithmetic number, because the mean of its divisors is an integer number (87587850).
Almost surely, 21113113112 is an apocalyptic number.
1113113112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1113113112 is an abundant number, since it is smaller than the sum of its proper divisors (1689698088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1113113112 is a wasteful number, since it uses less digits than its factorization.
1113113112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333815 (or 333811 counting only the distinct ones).
The product of its digits is 18, while the sum is 15.
The square root of 1113113112 is about 33363.3498318140. The cubic root of 1113113112 is about 1036.3658636344.
Adding to 1113113112 its reverse (2113113111), we get a palindrome (3226226223).
Subtracting 1113113112 from its reverse (2113113111), we obtain a palindrome (999999999).
The spelling of 1113113112 in words is "one billion, one hundred thirteen million, one hundred thirteen thousand, one hundred twelve".
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