Search a number
-
+
111313020281 is a prime number
BaseRepresentation
bin110011110101011000…
…1011110010101111001
3101122022121002022120212
41213222301132111321
53310432113122111
6123045252200505
711020304026631
oct1475261362571
9348277068525
10111313020281
1143231330741
12196a6609135
13a65c543398
14555d7336c1
152d6750a98b
hex19eac5e579

111313020281 has 2 divisors, whose sum is σ = 111313020282. Its totient is φ = 111313020280.

The previous prime is 111313020163. The next prime is 111313020283. The reversal of 111313020281 is 182020313111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107885971600 + 3427048681 = 328460^2 + 58541^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111313020281 is a prime.

It is a super-2 number, since 2×1113130202812 (a number of 23 digits) contains 22 as substring.

Together with 111313020283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111313020283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656510140 + 55656510141.

It is an arithmetic number, because the mean of its divisors is an integer number (55656510141).

Almost surely, 2111313020281 is an apocalyptic number.

It is an amenable number.

111313020281 is a deficient number, since it is larger than the sum of its proper divisors (1).

111313020281 is an equidigital number, since it uses as much as digits as its factorization.

111313020281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 111313020281 its reverse (182020313111), we get a palindrome (293333333392).

The spelling of 111313020281 in words is "one hundred eleven billion, three hundred thirteen million, twenty thousand, two hundred eighty-one".