| Base | Representation |
|---|---|
| bin | 10000001100110001010… |
| … | …101010011111101000000 |
| 3 | 10221102102111201201202221 |
| 4 | 100030301111103331000 |
| 5 | 121214340343400000 |
| 6 | 2211224054020424 |
| 7 | 143266506400333 |
| oct | 20146125237500 |
| 9 | 3842374651687 |
| 10 | 1113224200000 |
| 11 | 39a130048200 |
| 12 | 15b900647714 |
| 13 | 80c907582a3 |
| 14 | 3bc4791461a |
| 15 | 1de5693c61a |
| hex | 10331553f40 |
1113224200000 has 504 divisors, whose sum is σ = 3064728579192. Its totient is φ = 400857600000.
The previous prime is 1113224199977. The next prime is 1113224200001. The reversal of 1113224200000 is 24223111.
It can be written as a sum of positive squares in 12 ways, for example, as 1066246238464 + 46977961536 = 1032592^2 + 216744^2 .
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113224200001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3799399854 + ... + 3799400146.
It is an arithmetic number, because the mean of its divisors is an integer number (6080810673).
Almost surely, 21113224200000 is an apocalyptic number.
1113224200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1113224200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1532364289596).
1113224200000 is an abundant number, since it is smaller than the sum of its proper divisors (1951504379192).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1113224200000 is an equidigital number, since it uses as much as digits as its factorization.
1113224200000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 509 (or 468 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 1113224200000 its reverse (24223111), we get a palindrome (1113248423111).
The spelling of 1113224200000 in words is "one trillion, one hundred thirteen billion, two hundred twenty-four million, two hundred thousand".
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