Base | Representation |
---|---|
bin | 10000001100110001101… |
… | …011111001010100011111 |
3 | 10221102102220212111210110 |
4 | 100030301223321110133 |
5 | 121214343402321343 |
6 | 2211224424541103 |
7 | 143266610615424 |
oct | 20146153712437 |
9 | 3842386774713 |
10 | 1113230120223 |
11 | 39a133421151 |
12 | 15b902621793 |
13 | 80c91a4bb90 |
14 | 3bc48615d4b |
15 | 1de5720b833 |
hex | 10331af951f |
1113230120223 has 64 divisors (see below), whose sum is σ = 1733392483200. Its totient is φ = 629319794688.
The previous prime is 1113230120203. The next prime is 1113230120293. The reversal of 1113230120223 is 3220210323111.
It is not a de Polignac number, because 1113230120223 - 213 = 1113230112031 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1113230120223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113230120203) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6699753 + ... + 6863901.
It is an arithmetic number, because the mean of its divisors is an integer number (27084257550).
Almost surely, 21113230120223 is an apocalyptic number.
1113230120223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1113230120223 is a deficient number, since it is larger than the sum of its proper divisors (620162362977).
1113230120223 is a wasteful number, since it uses less digits than its factorization.
1113230120223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164428.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1113230120223 its reverse (3220210323111), we get a palindrome (4333440443334).
The spelling of 1113230120223 in words is "one trillion, one hundred thirteen billion, two hundred thirty million, one hundred twenty thousand, two hundred twenty-three".
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